x^2+88x-540=0

Solution for x^2+88x-540=0 equation:

x^2+88x-540=0

a = 1; b = 88; c = -540;
Δ = b2-4ac
Δ = 882-4·1·(-540)
Δ = 9904
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{9904}=\sqrt{16*619}=\sqrt{16}*\sqrt{619}=4\sqrt{619}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(88)-4\sqrt{619}}{2*1}=\frac{-88-4\sqrt{619}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(88)+4\sqrt{619}}{2*1}=\frac{-88+4\sqrt{619}}{2}
$